1.

Suppose that `F(n +1) =( 2f(n)+1)/2` for n = 1, 2, 3,.....and f(1)= 2 Then F(101) equals = ?A. 50B. 52C. 54D. none of these

Answer» Correct Answer - B
Given,
`F(n+1)=(2F(n)+1)/2`
`rArrF(n+1)-F(n)=1//2`
Hence, the given series is an A.P. with common difference 1/2 and first term being 2. F(101) is 101st term of A.P. given by
2+(101-1)(1/2)=52


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