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Suppose that `F(n +1) =( 2f(n)+1)/2` for n = 1, 2, 3,.....and f(1)= 2 Then F(101) equals = ?A. 50B. 52C. 54D. none of these |
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Answer» Correct Answer - B Given, `F(n+1)=(2F(n)+1)/2` `rArrF(n+1)-F(n)=1//2` Hence, the given series is an A.P. with common difference 1/2 and first term being 2. F(101) is 101st term of A.P. given by 2+(101-1)(1/2)=52 |
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