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Suppose that the electric field amplitude of an electromagnetic wave is E_(0)=120N/C and that its frequency is v=50.0 MHz.Find expressions for E and B. |
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Answer» SOLUTION :(a) `400 nT. 3.14 xx10^(8)" rad//s"1.05" rad//m ".6.00 m`. (B) `E={(120 N//C) sin (1.05" rad/m ")]x-(3.14xx10^(8)" rad/s")t]} HAT J` `B={(400 nT) sin (1.05" rad/m")]x-(3.14xx10^(8)" rad/s")t]} hat K` |
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