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Suppose that the electric field part of an electromagnetic wave in vacuum isE={(3.1 N//C) cos [(1.8 rad//m)y+(5.4xx10^(6)rad//s)t]}hat(i).a.What is the direction of propagation ?b.What is the wavelength lambda ?c.What is the frequency upsilon ?d. What is the amplitude of the magnetic field part of the wave ?e.Write an expression for the magnetic field part of the wave. |
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Answer» Solution :a.`-j` B.We have `E={3.14 N//C cos (1.8 rad//m)y+5.4xx10^(6)rad//s t}t` The standard EQUATION is `x=A sin [(2pi)/(T)t+(2pi)/(lambda)y]` Comparing the above equation,`(2pi)/(lambda)y=1.8y` `lambda = (2xx3.14)/(1.8)=3.5 m` c.We have`(2pi)/(T)t=5.4xx10^(6)t` `(1)/(T)=(5.4xx10^(6))/(2xx3.14)` `upsilon = 0.859xx10^(6)Hz` d.`c=(E_(0))/(B_(0))` `B_(0)=(E_(0))/(c )=(3.1)/(3xx10^(8))=(3.1xx10^(-8))/(3)=1.03xx10^(-8)T` e.`B={(1.03xx10^(-8)T)cos (1.8 rad//m)y+(5.4xx10^(6)rad//s)t}hat(k)` |
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