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Suppose that the electric field part of an electromagnetic wave in vacuum is vec(E )={(3.1 N//C)cos [(1.8 rad//m)y+(5.4xx10^(6)rad//s)]}hat(i)What is the wavelength lambda ? |
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Answer» SOLUTION :Comparing given EQUATION, `vec(E )=3.1 COS {(5.4xx10^(6))t+(1.8)y}hat(i)` (With all values in SI UNITS) with standard form `E=E_(0)cos (omega t + ky)` we get, `E_(0)=3.1 (N)/(C ) ""`…(2) `omega = 5.4xx10^(6)(rad)/(s) ""`....(3) `k=1.8(rad)/(m) ""`....(4) `therefore (2pi)/(lambda)=1.8 rArr lambda = (2xx3.14)/(1.8)=3.489 m` `~~3.5 m ""`....(5) |
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