1.

Suppose that the electric field part of an electromagnetic wave in vacuum is vec(E )={(3.1 N//C)cos [(1.8 rad//m)y+(5.4xx10^(6)rad//s)]}hat(i)What is the frequency v ?

Answer»

Solution :From equation (3),
`omega = 5.4xx10^(6)(rad)/(s)`
`therefore 2pi V=5.4xx10^(6)(rad)/(s)`
`therefore v=(5.4xx10^(6))/(2xx3.14)=8.599xx10^(5)Hz`
`~~86 " MHZ"`…(6)


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