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Suppose that the electric field part of an electromagnetic wave in vacuum is vec(E )={(3.1 N//C)cos [(1.8 rad//m)y+(5.4xx10^(6)rad//s)]}hat(i)What is the amplitude of the magnetic field part of the wave ? |
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Answer» Solution :ACCORDING to FORMULA, `c=(E_(0))/(B_(0))` `therefore B_(0)=(E_(0))/(c )` `=(3.1)/(3xx10^(8))` `therefore B_(0)=1.033xx10^(-8)T ~~ 10.3 NT ""`…(7) |
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