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Suppose the gravitational force varies inversely as the `n^(th) `power of distance. Then the time period of a planet in circular orbit of radius R around the sun will be proportional to-A. `R^(((n+1)/(2)))`B. `R^(((n-1)/(2)))`C. `R^(n)`D. `R^(((n-2)/(2)))` |
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Answer» Correct Answer - A `F=(GMm)/(r^(n))=momega^(2)r` `impliesomega=sqrt((GM)/(r^(n+1)))impliesT=(2pi)/(omega)=(r^((n+1)/(2)))` |
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