1.

Suppose the initial charge on the capacitor is 6 mC. What is the total energy stored in the circuit initially? What is the total energy at later time?

Answer»

SOLUTION :`E = (Q^2)/(2C) = ( (6 XX 10^(-3) )^2)/(2 xx 30 xx 10^(-6) ) = 0.6 J`
total energy is same for the later TIME .


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