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Suppose the initial charge on the capacitor is 6 mC. What is the total energy stored in the circuit initially? What is the total energy at later time? |
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Answer» SOLUTION :`E = (Q^2)/(2C) = ( (6 XX 10^(-3) )^2)/(2 xx 30 xx 10^(-6) ) = 0.6 J` total energy is same for the later TIME . |
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