InterviewSolution
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InterviewSolution
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Suppose the initial charge on the capactor in the above question is 6 mC. What is the total energy stored in the capactor intially ? What is the total energy at later time ? |
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Answer» Capacitance of the capacitor, C=`30muF=30xx10^(-6)F` Inductance of the inductor, L`=27mH=27xx10^(-3)H` Charge on the capacitor, Q=6mC=6`xx10^(-3)C` Total energy stored in the capacitor can be calculated by the relation `E=(1)/(2)(Q ^(2))/(C)` `=(1)/(2) xx ((6xx10^(-3))^(2))/(30xx10^(-6)) ` `=(6)/(10)=0.6J` Total energy at a later time will remain the same because energy is shared between the capacitor and the inductor. |
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