1.

Suppose the mass of a single Ag atom is m. Ag metal crystallizes in fcc lattice with unit cell of length a.The density of Ag metal in terms of a and m is

Answer»

`(4m)/(a^(3))`
`(2M)/(a^(3))`
`m/(a^(3))`
`m/(4a^(3))`

Solution :Density `=("Mass of the unit CELL")/("Volume of the unit cell")`
`=("No. of atoms" xx "Mass of each ATOM")/("Volume of the unit cell")`
`=(4xxm)/(a^(3))` (`:.` in fcc, no of atoms =4)


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