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Suppose the rest length of the box in figureis 30 light seconds. The train T_1 travels at a speed of 0.8c. Find the time elapsed between opening of D_1 and D_2 in the frame of T_1. |
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Answer» Solution :The BOX MOVES in the frame of `T_1` with a speed of 0.8c so that `gamma = 1 / (sqrt 1 - (0.8)^(2)) = 1 / 0.6` In this frame, `D_2` OPENS after `D_1`. Thetime elapsed between the openings of the doors is ` Lv / C^2 gamma = (30 light seconds ) xx (0.8 c) / C^(2) xx 0.6 ` ` (30 s ) C xx (0.8 c) / C^2 xx 0.6 = 40s`. |
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