Suppose the wavelength of the incident light is increased from `3000 Å` to `3040Å`. Find the corresponding change in the stopping potential. [Take the product `hc=12.4xx10^(-7)eVm)`]

Suppose the wavelength of the incident light is increased from `3000 �

1.	Suppose the wavelength of the incident light is increased from `3000 Å` to `3040Å`. Find the corresponding change in the stopping potential. [Take the product `hc=12.4xx10^(-7)eVm)`]
Answer» Correct Answer - `dV_(s)=(hc)/(e ).(dlambda)/(lambda^(2))= -(hc)/(228e)xx10^(7)= -5.5xx10^(-2)"volt"` `V_(s)=(hc)/(elambda)-(W)/(e )` On differentating `dV_(s)= -(hc)/(elambda^(2))(dlambda)= -5.5xx10^(-2) "volt"` `dV_(s)=(hc)/(e).(Deltalambda)/(lambda^(2))=(hc)/(228e)xx10^(7)=5.5xx10^(-2)"Volt"`

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Suppose the wavelength of the incident light is increased from `3000 Å` to `3040Å`. Find the corresponding change in the stopping potential. [Take the product `hc=12.4xx10^(-7)eVm)`]

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