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Suppose three real numbers `a`, `b`, `c` are in `G.P.` Let `z=(a+ib)/(c-ib)`. ThenA. `z=(ib)/(c )`B. `z=(ia)/(b)`C. `z=(ia)/(c )`D. `z=0` |
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Answer» Correct Answer - A::B `(a,b)` Let `r` be the common ratio of `G.P.a,b,c` we have `:.z=((a)/(b)+i)/((c )/(b)-i)=((1)/(r )+i)/(r-i)=(i)/(r )` `z=(ib)/(c )` or `(ia)/(b)` |
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