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Suppose, we think of fission of a " "_(26)^(56)Fe nucleus into two equal fragments, " "_(13)^(28)Al. Is the fission energetically possible ? Argue by working out Q of the process. Given m(" "_(26)^(56)Fe) = 55.93494 u and m(" "_(13)^(28)Al) = 27.98191 u. |
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Answer» Solution :Let the fission reaction be expressed as `" "_(26)^(56)Fe to " "_(13)^(28)Al+ " "_(13)^(28)Al+Q` Here initial mass = m[`" "_(26)^(56)Fe]=55.93494 U` and final mass` = 2 m[" "_(13)^(28)Al] =2xx 27.98191 = 55.96382 u` `THEREFORE` GAIN in mass during fission reaction = 0.02888 u `therefore` Energy involved `Q = -0.02888 xx 931.5 MeV = - 26.90 MeV` As the process is ENDOTHERMIC and energy of 26.90 MeV is consumed i.e., initially we must supply an energy of 26.90 MeV to start the reaction. It shows that the fission is not energetically possible. |
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