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Answer» 3-hydroxybutanoic acid +3-hydroxypentanoic acid 2-hydroxybutaoic acid +2-hydoxypropanoic acid 3-chlorobutanoic acid +3-chloropentanoicacid 2-chlorobutanoic acid +3-methylpentanoic acid. Solution :`underset("3-Hydroxybutanoic acid")(nCH_(3)-overset(OH)overset(|)(CH)-CH_(2)COOH)+underset("3-Hydroxypentanoic acid")(nCH_(3)CH_(2)-overset(OH)overset(|)(CH)-CH_(2)COOH) tounderset(PHBV)([--O-underset(CH_(3))underset(|)(CH)-CH_(2)-underset(O)underset(||)C-underset(CH_(2)CH_(3))underset(|)(CH)-CH_(2)-underset(O)underset(||)(C)--]_(n)`
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