1.

(t_(1))/(4) can be taken as the time taken for the concentration of a reactant to drop to (3)/(4) of its initial value. If the rate constant for a first order reaction is k, the (t_(1))/(4) can be writen as

Answer»

`(075)/(K)`
`(0.69)/(k)`
`(0.29)/(k)`
`(0.10)/(k)`

Solution :`t_((1)/(4))=(2.303)/(k)"LOG"(1)/((3)/(4))=(2.303)/(k)"log"(4)/(3)=(2.303)/(k)("log"4-"log"3)=(2.303)/(k)(2"log"2-"log"3))=(2.303)/(k)(2times0.301-0.4771)=(0.29)/(k)`


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