1.

T.V. transmission tower at a particular station has a height of 160 m. (a) What is the coverage range ? (b) How much population is covered by transmission, if the average population density around the tower is 1200 per km^(2) ? (c ) What should be the height of tower to double the coverage range

Answer»

SOLUTION :(a) Coverage range `d=sqrt(2Rh)`
`=sqrt(2xx6400xx10^(3)xx160m)=45.254` KM
(b) Population covered = (population density) `xx` (area covered) = `(1200)xx(pid^(2))`
`=(2400pi" RH")=2400xx3.14xx6.4xx10^(3)xx0.16=77.17` lac
(c) Therefore civerage range can be soubled by making height of the tower FOUR times to 640m. So, height of the tower should be increased by 480 m


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