Saved Bookmarks
| 1. |
Taking the Bohr radius as a_(0)= 53 pm the radius of Li^(++) ion in its ground state, on the basis of Bohr's model, will be about. |
|
Answer» 53 pm `r_(n)=(a_(0)n^(2))/(Z)` TAKING `Z=3` for `Li^(++)` ION and n=1 for its ground state, `r_(1)=(53)XX((1)^(2))/(3)` `:. r_(1)(53)xx((1)^(2))/(3)` `:.r_(1)=17.67` pm `~~18` pm (picometer) |
|