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Tangents PA and PB are drawn to a circle with point P outside the circle, line joining P and centre intersect chord AB at M then, Prove that `/_OPA = /_OAM` |
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Answer» `/_PAM` and `/_PBM` PA=PB PM=PM `/_APM=/_BPM` `/_PAM cong /_PBM` `/_OAM=x` `/_PAO=90` `/_PAM=90-/_OAM` `/_APM=/_OAM` `/_APM=/_APO=/_OPA` `/_OPA=/_OAM`. |
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