1.

Tangents PA and PB are drawn to a circle with point P outside the circle, line joining P and centre intersect chord AB at M then, Prove that `/_OPA = /_OAM`

Answer» `/_PAM` and `/_PBM`
PA=PB
PM=PM
`/_APM=/_BPM`
`/_PAM cong /_PBM`
`/_OAM=x`
`/_PAO=90`
`/_PAM=90-/_OAM`
`/_APM=/_OAM`
`/_APM=/_APO=/_OPA`
`/_OPA=/_OAM`.


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