Saved Bookmarks
| 1. |
Tell me this answer. if you give wrong answer then I will report your answer |
|
Answer»
X and Y if 2X+3Y=[ 2 4
3 0
] 3X+2Y=[ 2 −1
−2 5
] → let ASSUME [ 2 4
3 0
] = A [ 2 −1
−2 5
] = B →2x+3y=A __ (i) 3x+2y=B __ (ii) → MULTIPLE equation (i) with 2 & equation (ii) with (3) 4x+6y=2A 9x+6y=3B ________________ −5x=2A−3B ∴x= 5 −1
[2A−3B] ∴x= 5 3B
− 5 2A
= 5 3
[ 2 −1
−2 5
]− 5 2
[ 2 4
3 0
] =[ 6/5 −3/5
−6/5 3
]−[ 4/5 8/5
6/5 0
] =[ 6/5 −3/5
−4/5 −8/5
−4/5 3
−6/5 −0
] ∴x=[ 1/5 −11/5
−12/5 3
] → value of x put in equation (i) ∴[ 2/5 −22/5
−24/5 6
]+3y=[ 2 4
3 0
] ∴3y=[ 2−2/5 4+22/5
3+24/5 0−6
]=[ 8/5 42/5
39/5 −6
] |
|