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Temperature at the foot of a mountain is 30^(@)C and pressure is 760 mm whereas at the top of the mountain these are 0^(@)C and 710 mm. compare the densities of the air at the foot and at the top of the mountain. |
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Answer» <P> Solution :`d=(Pm)/(RT) rArr (d_(1))/(d_(2))=(P_(1))/(T_(1))xx(T_(2))/(P_(2))=(760 mm)/(303 K) xx (273 K)/(710 mm) =(0.964)/(1) =0.964` |
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