1.

Temperature gradient in a rod 0.5 m long is 80^(@)Cm^(-1) The temperature of the hotter end is 60^(@)C. The temperature of cooler end will be :

Answer»

`40^(@)C`
`10^(@)C`
`20^(@)C`
`12^(@)C`.

SOLUTION :Here `(T_(1)-T_(2))/(x)=80`
`rArr(60-T_(2))/(0*5)=80""rArrT_(2)=+20^(@)C`.
THUS correct choice is (d).


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