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Temperature gradient in a rod 0.5 m long is 80^(@)Cm^(-1) The temperature of the hotter end is 60^(@)C. The temperature of cooler end will be : |
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Answer» `40^(@)C` `rArr(60-T_(2))/(0*5)=80""rArrT_(2)=+20^(@)C`. THUS correct choice is (d). |
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