Temperature of 1 mole of an ideal gas is increased from 300K to 310K under isochoric process. Heat supplied to the gas in this process is Q=25R, where R=universal gas constant. What amount of work has to be done by the gas if temperature of the gas decreases from 310K to 300K adiabatically?

Temperature of 1 mole of an ideal gas is increased from 300K to 310K u

1.	Temperature of 1 mole of an ideal gas is increased from 300K to 310K under isochoric process. Heat supplied to the gas in this process is Q=25R, where R=universal gas constant. What amount of work has to be done by the gas if temperature of the gas decreases from 310K to 300K adiabatically?
Answer» `DeltaQ=nC_(V)DeltaT` `therefore25R=(1)(C_(V))(310-300)` or `C_(V)=(5)/(2)R` As the gas is diatomic `gamma=1.4` Now work done in adiabatic process `W=(nR(T_(1)-T_(2)))/(-1)=((1)(R)(310-300))/(1.4-1)=25R`

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Temperature of 1 mole of an ideal gas is increased from 300K to 310K under isochoric process. Heat supplied to the gas in this process is Q=25R, where R=universal gas constant. What amount of work has to be done by the gas if temperature of the gas decreases from 310K to 300K adiabatically?

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