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Temperature of a conductor increases by 5^(@)C passing electric current for same time. The increase in its temperature when double current is passed through 1he same conductor the same time is ..... ""^(@)C. |
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Answer» 10 ` H = (I^(2) Rt)/(J)` MS `Delta theta = (I^(2) Rt)/(J) ` `therefore Delta theta prop I^(2)` `therefore Delta theta_(1)prop I_(1)^(2)` `therefore Delta theta_(2) prop I_(2)^(2) ` ` therefore (Delta theta_(2))/(Delta theta_(1))= ((I_(2))/(I_(1)) )^(2) ` `therefore Delta theta_(2) = ((I_(2))/(I_(1)))^(2) Delta theta_(1)` Now `I_(2)= 2I_(1)` `therefore Delta theta_(2) = ((2I_(1))/(I_(1)))^(2) XX 5 ` `therafore Delta theta_(2) = 20""^(@)C` |
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