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Temperature of one mole of helium gas is increased by `1^(@)C`. Hence,the increasein its internal energy will beA. 2 calB. 3 calC. 4 calD. 5 cal |
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Answer» Correct Answer - B `C_(v) = ((DeltaU)/(DeltaT))_(V)`or` DeltaU = C_(v)DeltaT` But for monoatomic gas, `C_(v)= (3)/(2) R`. Also `DeltaT =1^(@)` (Given) Hence, `DeltaU = C_(v)DeltaT = (3)/(2) R = (3)/(2) xx2 = 3 cal` |
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