1.

Ten grams of a gas occupies 2 L at STP. At what temperature will the volume of the same quantity of a gas becomes double at the same pressure ?

Answer»

273K
`-273^(@)C`
546K
`546^(@)C`

Solution :`( V_(1))/( T_(1)) = (V_(2))/( T_(2))` (Charles. law)
`T_(2) = ( 4L xx 273)/( 2L) = 546K`


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