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Ten grams of a gas occupies 2 L at STP. At what temperature will the volume of the same quantity of a gas becomes double at the same pressure ? |
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Answer» Solution :`( V_(1))/( T_(1)) = (V_(2))/( T_(2))` (Charles. law) `T_(2) = ( 4L xx 273)/( 2L) = 546K` |
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