

InterviewSolution
Saved Bookmarks
1. |
Ten millilitre ofa mixture of methane, ethylene, and carbon dioxide was exploded with excess of air: After the explosion, there was contraction of 17 ml and after treatment with `KOH`, there was a further contraction of 14 ml. What was the composition of the mixture? |
Answer» Let the volume of `CH_4` be x mL Volume of `(CH_2=CH_2)=ymL` Volume of `CO_2=[10-(x+y)]mL` (a). `CH_4(g)+2O_2(g)toCO_2(g)+2H_2O(l)` (b). `CH_2=CH_2(g)+3O_2(g)to2CO_2(g)+H_2O(l)` Volume of `CO_2` absorbed by `KOH=14mL` `thereforey=4mL` Volume of gaseous reactant `=` volume of gaseous production`+`constraction `x+2x+y+3Y=x+2y+17` `3x+4y-x-2y=17` `2x+2y=17` `2x+2xx4=17` `2x=9` `x=4.5mL` Volume of `CH_4=4.5mL` Volume of `CH_2=CH_2=4mL` Volume of `CO_2=10-(4.5+4)=1.5mL` |
|