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tens digit of a two digit number is 3 more than its unit digit . the sum of the original number and the number formed by reversing its digit is 55. find the numbers. |
| Answer» ORIGINAL number = 41Reversed number = 14Step-by-step explanation:Given:Tens digit is 3 more than the the unit digitSum of the original number and reversed number is 55To Find:The numbersSolution:Let us assume the ten's digit of the number as xLet us assume the one's digit of the number as yBy given,X = 3 + y----(1)Hence the original number will be,The original number = 10x + yNow,The reversed number = 10y + xBy given,10x + y + 10y + x = 55Now SUBSTITUTE the value of x from equation 110 (3 + y) + y + 10y + 3 + y = 5530 + 10y + y + 10y + 3 + y = 5522y + 33 = 5522y = 55 - 3322y = 22 y = 22/22 y = 1Hence the digit in the unit's place is 1Now substitute the value of y in equation 1X = 3 + 1x = 4Hence the digit in the ten's place is 4Therefore,The original number = 10x + yThe original number = 10 × 4 + 1 = 41Therefore the original number is 41The reversed number is given by,Reversed number = 10y + xReversed number = 10 × 1 + 4 = 14Hence the reversed number is 14Verification:Ten's digit = One's digit + 34 = 1 + 34 = 4Original number + Reversed number = 5541 + 14 = 5555 = 55Hence verified. | |