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Tension of a string is 6.4 N and load is applied to it at its lower end of a string is 0.1 kg .If the length of string is 6 m , then its angular velocity will be `A. `3 rad//s`B. `4 rad//s`C. `2 rad//s`D. `1 rad//s` |
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Answer» Correct Answer - A `T=m r omega ^(2)` `therefore omega ^(2)=(T)/(mr)=(6.4)/(0.1xx6)` `omega ^(2)=10` `omega =sqrt(10)=3 rad //s `. |
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