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Terminal voltage of battery of 1.25 V and emf of battery" 1.5V ,so internal resistance of battery is ...... Omega. |
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Answer» 2 V = E - Ir `= E -(Er)/(R + r) = (ER+ Er - Er)/(R + r)` `therefore V =(ER)/(V) ` `therefore R + r = (ER)/(V)` `therefore r = (ER)/(V) - R` ` = (1.5 xx 10^(4))/(1.25) - 10^(4)` = ` 1.2 xx 10^(4) - 10^(4)= 0.2 xx 10^(4)` `therefore r = 2000 OMEGA` |
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