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That angle triangle ABC with AB is equal to 4 cm BC is equal to 3.5 cm and AC is equal to 4 cm what type of triangle is this |
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Answer» Step-by-step EXPLANATION: Share ANSWER Steps: 1. draw base AB=4cm 2. with A as center, with a scale of 5cm as radius draw an arc and with B as center, with a scale of 6cm as radius draw an arc. 3. let C be the point of intersection of the above 2 lines. 4. draw a RAY AX making an acute angle with line AB on the opposite side if the vertex C. 5. mark 3 points A1,A2,A3 such tha A1A2=A2A3=A3A1 6. join A3B and draw a parallel line B ′ A2 7. draw a line parallel to BC to intersect AC at C ′
Thus AB ′ C ′ is a required triangle. Justification; By construction, AB AB ′
= AA3 AA2
= 3 2
also B ′ C ′ ∥BC ∴∠AB ′ C ′ =∠ABC In △AB ′ C ′ ,△ABC ∠A=∠A ∠AB ′ C ′ =∠ABC △AB ′ C ′ ∼△ABC ⇒ AB AB ′
= AC AC ′
= BC B ′ C ′
∴ AB AB ′
= AC AC ′
= BC B ′ C ′
= 3 2
solution |
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