1.

The 0.1 molal aqueous solution of glucose boils at 100. 16^(@)C. The boiling point of 0.5 molal aqueous solution of sucrose will be

Answer»

`500.80 ^(@)C`
`100.80^(@) C`
`20.16 ^(@)C`
`20.8^(@)C`

Solution :As the SOLVENT is same in both solution `K_(B)` is constant we have, `Delta T = K_(b) XX m`
For 0.1 MOLE solution, `Delta T = 100.6 - 100 = 0.16^(@)C`
:. For 0.5 molal solution `delta T =0.5 xx 0.16 = 0.8^(@) C`
:. B. pt. of sucrose solution `= 100.8^(@) C`


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