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The 11th term of the AP: –5, (–5/2), 0, 5/2, …is(A) –20 (B) 20 (C) –30 (D) 30 |
Answer» (B) 20 Explanation: First term, a = – 5 Common difference, d = 5 – (-5/2) = 5/2 n = 11 We know that the nth term of an AP is an = a + (n – 1)d Where, a = first term an is nth term d is the common difference a11 = – 5 + (11 – 1)(5/2) a11 = – 5 + 25 = 20 |
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