1.

The 11th term of the AP: –5, (–5/2), 0, 5/2, …is(A) –20 (B) 20 (C) –30 (D) 30

Answer»

(B) 20

Explanation:

First term, a = – 5

Common difference,

d = 5 – (-5/2) = 5/2

n = 11

We know that the nth term of an AP is

an = a + (n – 1)d

Where,

a = first term

an is nth term

d is the common difference

a11 = – 5 + (11 – 1)(5/2)

a11 = – 5 + 25 = 20



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