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The 14 term of an AP is twice at 9 term . if it's 6 term is -8 then find its sum of its 20 term​

Answer» 0 Step-by-step explanation: T12=a +11D -13=a+11d a=-13-11d                            --(i) S4=2(2(a)+3D) 24=2(2(-13-11d)+3d) On simplification, d=-2 and a=9 now, S10=5[2(9)+9(-2)] THEREFORE S10=0


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