1.

The 6th and the 17th terms of an AP are 21 and 54 respectively . The first term of the AP is _?​

Answer»

Answer:

A6 = 21

a17 = 54

an = a +(n-1) d

a6 = a +(6 - 1) d

21 = a+ 5d............ (i)

a17 = a + ( 17 - 1)d

54 = a + 16d....(ii)

by SUBSTITUTION method,

21 - 5d = a.........(iii)

SUBSTITUTE iii in ii

54 = 21 - 5d + 16d

54 - 21 = 11d

33 = 11d

d = 3

substitute d in i

21 = a + 5d

21 = a + 5*3

21 - 15 = a

a=6

therefore the first term of the ap is 6

AP : 6,9,12,15.......

hope it helps you...



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