Saved Bookmarks
| 1. |
The 7th term and 13th terms of an AP are 34 respectively .find the first three terms |
|
Answer» question not properly 13th TERM not fill in question, PUT I put behalf me. USE only this method, you put your value. answer:-22,24,26 Explanation: An= a+(n-1) d 7th term for= a+6d 34=a+6d
a= 34-6d........(1) 13th term= a+12d
13th term not available so I put for behalf me= 56 and you put right value =a+12d.....(1) put value of a from...... (1) so, 56= 34-d+12d 56= 34+11d 11d=56-34 d=22÷11=2 d=2 put in... (1) so a= 34-6(2) a= 34-12=22 first three term are 22,24,26
|
|