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The a value of k for which the systemof equationsx + 2y = 53x+ky+15=0 |
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Answer» y = 30 / (6-k)x = - (30+5k) / 60Step-by-step explanation:(The question is incomplete but you can always find the value of k having given the VALUES of x & y from the answer given)given x+2y = 5=> x = 5-2yalso given that 3X +ky+15 = 0ie, 3(5-2y) + ky + 15 = 0=> 15-6y+ky+15=0=> y(6-k) = 30=> y = 30 / (6-k)also x = 5 - 2( 30 / (6-k) ) = 5 - (60/(6-k)) = [ (30-5k) - 60] / 60 x = - (30+5k) / 60 |
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