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The acceleration a' in ms-2 of a particle is given by a = 3t^2 +2t+2, where is the time. If the particle starts with a velocity v = 2 m s-at i=0 then velocity at the end of 2 sec is: |
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Answer» 12`m s^(-1)` `=u+int_(0)^(t)(3T^(2)+2T+2)dt` `=u+[(3t^(3))/(3)+(2t^(2))/(2)+2t]_(0)^(2)=2+8+4+4` =18`ms^(-1)` |
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