1.

The acceleration a of a body, starting from rest varies with time t following the cquation a= 3t + 4. The velocity of the body at timet =2 s will be

Answer»

`10 m s^(-1)`
`18 ms ^(-1)`
`14 ms^(-1)`
`26 ms^(-1)`

SOLUTION :`a=3t+4or (dv)/(DT)=3t+4or intdv=int(3t+4)dt`
or `nu=(3)/(2)t^(2)+4t=(3)/(2)xx2^(2)+4xx2"" `[At t=2s ]
=6+8 =14m/s.


Discussion

No Comment Found

Related InterviewSolutions