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The acceleration due to gravity at height `R` above the surface of the earth is `g/4`. The periodic time of simple pendulum in an artifical satellie at this height will be :-A. `T = 2pisqrt((2l)/(g))`B. `T = 2pisqrt((l)/(2g))`C. zeroD. infinity |
Answer» Correct Answer - D In an artificial satellite `g_(eff) = 0 rArr T = oo` |
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