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The acceleration due to gravity on a planet of mass `10^(25)` Kg and radius 2580 Km in `ms^(-2)` isA. 1B. 10C. 20D. 100 |
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Answer» Correct Answer - d `g=(GM)/(R^(2))=(6.67xx10^(-11)xx10^(25))/((2580xx10^(3))^(2))` `=(6.67xx10^(14))/(6.66xx10^(12))=10^(+2)=100ms^(-1)` |
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