InterviewSolution
Saved Bookmarks
| 1. |
The acceleration due to gravity on the planet A is 8 times the acceleration due to gravity on the planet B. A man jumps to a height of 2.5 m on the surface of A. What is the height of jump by the same person on the planet B ?A. 12 mB. 16 mC. 20 mD. 24 m |
|
Answer» Correct Answer - C Suppose that the man jumps with the same initial velocity (u) on both the planets. `because u^(2)=2gh " " therefore h=(u^(2))/(2g)` `therefore (h_(A))/(h_(B))=(u^(2))/(2g_(A))xx(2g_(B))/(u^(2))=(g_(B))/(g_(A))` But `h_(A)=2.5 m` and `g_(A)=8g_(B)` `therefore h_(B)=8xx1.5=20 m` |
|