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The acceleration due to gravity on the planet `A` is `9` times the acceleration due to gravity on planet `B`. A man jumps to a height of `2m` on the surface of `A`. What is the height of jump by the same person on the planet `B`?A. `2/3m`B. `2/9m`C. `18m`D. `6m` |
Answer» Correct Answer - C Applying conservation of total mechanical energy principle `1/2mv^(2)=mg_(A)h_(A)+mg(B)h_(B)` `implies g_(A)h_(A)=g_(B)h_(B)` `implies h_(B)=((g_(A))/(g_(B)))h_(A)=9xx2=18m` |
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