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The acceleration due to gravity on the surface of the moon is 1.7m/s^2 .What is the time period of a simple pendulum on the moon if its time period on earth is 3.5 sec? (take g on earth as 9.8m/s^2. |
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Answer» ation DUE to gravity on the surface of moon, g′=1.7ms−2Acceleration due to gravity on the surface of EARTH, g=9.8ms−2Time period of a SIMPLE pendulum on earth, T=3.5sT=2πglwhere, l is the length of the pendulum∴l=(2π)2T2×2=4×(3.14)2(3.5)2×9.8mThe length of pendulum REMAINS CONSTANTON moon's surface, time period, T′=2πg′l=2π1.74×(3.14)2(3.5)2×9.8=8.4 sHence, the time period of the simple pendulum on the surface of moon is 8.4 s. |
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