The acceleration of a particle is `a = - 100x + 50`. It is released from `x = 2`. Here, `a` and `x` are in SI unitsA. the particle will perform SHM of amplitude `2m`B. the particle will perform SHM of amplitude `1.5 m`C. the particle will perform SHM of time period `0.63 s`D. the particle will have a maximum velocity of `15 m//s`

The acceleration of a particle is `a = - 100x + 50`. It is released fr

1.	The acceleration of a particle is `a = - 100x + 50`. It is released from `x = 2`. Here, `a` and `x` are in SI unitsA. the particle will perform SHM of amplitude `2m`B. the particle will perform SHM of amplitude `1.5 m`C. the particle will perform SHM of time period `0.63 s`D. the particle will have a maximum velocity of `15 m//s`
Answer» Correct Answer - B::C::D `a = 0` at `x = 0.5 m` and particle is released from `x = 2m` Hence, `A = 2 - 0.5` `= 1.5 m` `omega^(2) = 100` `:. omega = 10 rad //s` `T = (2pi)/(omega) = (2pi)/(10)` `= 0.63 s` `v_(max) = omega A = (10)(1.5)` ` = 15m//s`

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