The acceleration of the moon just before it strikes the earth in the p

1.	The acceleration of the moon just before it strikes the earth in the previous question is(a) 10m/s2 (b) 0.0027m/s2 (c) 6.4m/s2 (d) 5.0m/s2.
Answer» (c) 6.4m/s² . Explanation: When the moon strikes the earth its center is R/4 above the surface of the earth. So the acceleration of the moon will be calculated at R+R/4 = 5R/4 away from the center of the earth. Since the acceleration is inversely proportional to the square of the distance, the acceleration of the moon at the time of strike = g{R/(5R/4)}² = g(4/5)² = 16g/25 =160/25 =6.4 m/s².

The acceleration of the moon just before it strikes the earth in the previous question is(a) 10m/s2 (b) 0.0027m/s2 (c) 6.4m/s2 (d) 5.0m/s2.

Answer»

(c) 6.4m/s² .

Explanation:

When the moon strikes the earth its center is R/4 above the surface of the earth. So the acceleration of the moon will be calculated at R+R/4 = 5R/4 away from the center of the earth. Since the acceleration is inversely proportional to the square of the distance, the acceleration of the moon at the time of strike

= g*{R/(5R/4)}² = g*(4/5)² = 16g/25 =160/25 =6.4 m/s².

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The acceleration of the moon just before it strikes the earth in the previous question is(a) 10m/s2 (b) 0.0027m/s2 (c) 6.4m/s2 (d) 5.0m/s2.

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