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The acceleration time graph of a particle moving along a straight line is shown in figure .At what tim the particle acquires its initial velocity. |
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Answer» SOLUTION :`a=a_(0)t+a_(1)`,0,a=`a_(1)`=10,a=0 at t=4 seconds. 0=+4`a_(0)`+10,`a_(0)`=-2.5 a=2.5 t+10,`(DV)/(DT)`=-2.5t+10 `int`dv=`int`(-2.5t+10)dt, V=`-2.5(t^(2))/(2)`+10t+c t=0,C=`v_(0), v=-2.5(t^(2))/(2)+10t+v_(0)` `v=v_(0)-2.5(t^(2))/(2)+10t=0,2.5(t^(2))/(2)=10t` t=8 seconds 
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