1.

The acidic substance in vinegar is acetic acid `(CH_(3)COOH)`. When `6.0 g` of a certain vinegar was titrated with `0.1MNaOH`. `40.11 mL` of base had to be added to reach the equivalence point. What per cent by mass of this sample of vinegar is acetic acid?

Answer» Meq. of acetic acid = Meq. of `NaOH`
`(w)/(60)xx1000= 0.1xx40.11`
`w= 0.241 g`
`:. %` of acetic acid in vinegar `=(0.241)/(6)xx100= 4.01`


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