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The activation energy for the reaction, 2" HI "(g)toH_(2)(g)+I_(2)(g), is 209.5" kJ mol"^(-1) at 581 K. Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy. |
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Answer» Solution :FRACTION of molecules having energy equal to or GREATER than ACTIVATION energy `=x=(n)/(N)=e^(-E_(a)//RT)` `:.LNX=-(E_(a))/(RT)" or "logx=-(E_(a))/(2.303"RT")` or `logx=-(209.5xx10^(3)" J mol"^(-1))/(2.303xx8.314" JK"^(-1)mol^(-1)xx581" K")=-18.8323` `:.x=" Antilog"(-18.8323)="Antilog "bar(19).1677=1.471xx10^(-19)` |
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