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The activation energy for the reaction 2HI_((g))toH_(2(g))+I_(2(g)) is 209.5 KJ mol^(-1) at 581 K.Calculate the fraction of molecules of reactants having energy equal to or freater than activation energy. |
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Answer» SOLUTION :FRACTION of molecules =`e^(-E_(a))/(RT)` `X=e^((209.5xx1000)/(8.314xx581))` `X=e^(-43.37)` `=1.461xx10^(-19)` OR `therefore K=A e^(-(E_(a))/(RT))` `therefore (k)/(A)=e^(-(E_(a))/(RT))` [But ,`(k)/(A)`=Fraction of molecule=X] `therefore X=-e^(-(E_(a))/(2.303RT)` `therefore log X=-(209.5xx10^(3)J mol)/(2.303xx8.134 J K^(-1)mol^(-1)xx581K)` |
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